5[3y+12]=6[5y+20]

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Solution for 5[3y+12]=6[5y+20] equation:


Simplifying
5[3y + 12] = 6[5y + 20]

Reorder the terms:
5[12 + 3y] = 6[5y + 20]
[12 * 5 + 3y * 5] = 6[5y + 20]
[60 + 15y] = 6[5y + 20]

Reorder the terms:
60 + 15y = 6[20 + 5y]
60 + 15y = [20 * 6 + 5y * 6]
60 + 15y = [120 + 30y]

Solving
60 + 15y = 120 + 30y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-30y' to each side of the equation.
60 + 15y + -30y = 120 + 30y + -30y

Combine like terms: 15y + -30y = -15y
60 + -15y = 120 + 30y + -30y

Combine like terms: 30y + -30y = 0
60 + -15y = 120 + 0
60 + -15y = 120

Add '-60' to each side of the equation.
60 + -60 + -15y = 120 + -60

Combine like terms: 60 + -60 = 0
0 + -15y = 120 + -60
-15y = 120 + -60

Combine like terms: 120 + -60 = 60
-15y = 60

Divide each side by '-15'.
y = -4

Simplifying
y = -4

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